an extern force of 5 N changes the velocity of a body of mass 2kg from 5m/sto 7m/s.the time for which the force has been applied is
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HERE IS YOUR ANSWER
GIVEN :
INITIAL VELOCITY(U) = 5M/S
FINAL VELOCITY (V) = 7M/S
FORCE = 5 N
MASS = 2 KG
WE KNOW THAT.
FORCE = MASS × ACCELERATION
5 = 2 × ACCELERATION
ACCELERATION(A) = 2.5 M/S^2
WE ALSO KNOW THAT
V = U + AT. ( T IS TIME )
7 = 5 + 2.5 × T
T = 2/2.5
T = 0.8 seconds
TIME = 0.8 SECONDS
HOPE MY ANSWER IS CORRECT
GIVEN :
INITIAL VELOCITY(U) = 5M/S
FINAL VELOCITY (V) = 7M/S
FORCE = 5 N
MASS = 2 KG
WE KNOW THAT.
FORCE = MASS × ACCELERATION
5 = 2 × ACCELERATION
ACCELERATION(A) = 2.5 M/S^2
WE ALSO KNOW THAT
V = U + AT. ( T IS TIME )
7 = 5 + 2.5 × T
T = 2/2.5
T = 0.8 seconds
TIME = 0.8 SECONDS
HOPE MY ANSWER IS CORRECT
abdeshs351:
thanks 0.8 is correct
Answered by
2
Answer:
Hey mate
answer is 0.8 second
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