Physics, asked by nalinkerketta, 1 year ago

an helicopter flying with a velocity of 70 km/h at a height of 490m when helicopter just a bow the targat boom strapped how for the bomb fall from the target​

Answers

Answered by Devkaran1
0

Answer:range ?

Range = initial velocity × time --1

Time for projectile = square root of 2gh

Convert 70 kmph in m/s

And then use equation 1

Similar questions