Question

An hourly requirement of an astronaut can be satisfied by the energy released
when 34 grams of sucrose is burnt in his body. How many grams of oxygen
would he require to carry in space to meet his requirement for one day?

Answer 1

Chemical Formula of the Sucrose = C₁₂H₂₂O₁₁

Molecular Mass = 342 g.

Mass of O present in Sucrose = 176 g.

∴ 342 g of Sucrose is required to form of the 176 g of the Oxygen by the Astronaut in 1 hrs.

∴ 1 g of Sucrose is required to form of the 176/342 g of the Oxygen by the Astronaut in 1 hrs.

∴ 34 g of Sucrose is required to form of the 176/342 × 34 g = 17.49 g of the Oxygen by the Astronaut in 1 hrs.

Therefore, In 24 hrs, Amount of Oxygen Required = 17.49 × 34 g

= 594.66 g.

Hope it helps.

Answer 2

The reaction will be C12H22O11 +12O2 --> 12CO2 +11H2O AND THIS IS THE CORRECT ANS. not the 1st one u got. See the attachment.  ☺