Question

An Ice-cream cafe has 200 customers every day. 60% of them like vanilla flavor and 80% of them like mango flavor. What is the probability, if one of the customers selected randomly and what is the joint probability of “ordering both vanilla and mango ice-cream” event and “not ordering both vanilla and mango ice-cream” event?

Answer 1

Answer:

both ordering would be 0.5, both not ordering would be 0.1

Step-by-step explanation:

Answer 2

Answer:

P(ordering both mango and vanilla) = 12/25

P(not ordering both vanilla and mango) = 13/25

Step-by-step explanation:

The number of customers who prefer Vanilla flavor = 60/100 × 200 = 120

The number of customers who prefer mango flavor = 80/100 × 200 = 160 customers.

The probability that a customer asks for vanilla ice cream = 120/200 = 3/5

The probability that a customer orders mango flavor = 160/200 = 4/5

The probability that a customer orders both mango and vanilla is given by:

P(Mango and Vanilla) = P(Mango) × P(Vanilla)

= 3/5 × 4/5 = 12/25

The probability that a customer orders neither of the flavors = 1 - P(ordering mango and vanilla flavor)

Writing this we have:

= 1 - 12/25

= 25/25 - 12/25 = 13/25