Question

The average depth of Indian ocean is about 3000m calculate the fractional compression Delta v upon vof water at the bottom of the ocean given that the bulk modulus of water is 2.2into 10to the power 9 NMsqare take g equal to 10ms

Answer 1

Given :

• Ocean depth = 3000 m
• Bulk modulus = 2.2 x 10^9 Pa
• g = 10 m/s²

To Find :

• percent fractional comparison of water at the bottom of the ocean

Solution :

Hydrostatic pressure

$\large \underline{ \bf p = h \: \rho \: g} \\ \\ \implies \bf 3000 \times {10}^{3} \times 10$

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Fractional compression

$\large\underline{ \bf \dfrac{\delta V }{V} = \dfrac{p}{B}} \\ \\ \bf\implies \frac{3000 \times {10}^{3 \times} \times 10}{2.2 \times {10}^{9} } \\ \\ \bf\implies1.36 \times {10}^{ - 2}$

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% Fractional compression

$\large \underline{\bf \frac{ \delta V}{V} \times 100} \\ \\ \bf \implies1.36 \times {10}^{ - 2} \times 100 \\ \\ \bf \implies1.36 \: \%$

Answer 2

Given:

ocean depth = 3000m

bulk modulus=2.2 × 10^9 pascal

g=10m/s^2

to find :

percent fractional comparison at the water of bottom of the ocean.

solution:

hydrostatic pressure :

P = h ρ g

=> 3000 × 10^3 × 10

fractional comparison:

δV/V ×100

=> 1.36 × 10^-6 × 100

=> 1.36%