Question

an iceberg float in freshwater with a part of its outside the water calculate the fraction of volume outside the water (p ice =900 kg/m3,p water=1000kg/m3)




Urgent solution pls
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Answer 1

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Answer:

Density of ice = 917 kg/m^3

Density of water = 1000 kg/m^3

According to the Floatation principle,

v/V = density of substance/density of liquid

= 917/1000 or, 0.917

This means that 917/1000 of the ice's total volume will be above the surface of water.

So, the part below water is:

1-917/1000

= 83/1000 or, 0.083

Ans: 83/1000 of the ice's total volume will be inside the water.

Hope this helps.