Question

An iceberg is floating in sea water. The density of ice is 0.92 g/cc and that of sea water is 1.03 g/ cc. The percentage of the iceberg which will be below the surface of water is

Answer 1

Volume above water = V

volume below water = V'

seawater density x V' = ice density x V 

1.03 x V' = 0.92 x V 

V'/V = fraction below water = 0.89

Fraction above water = 1 - fraction below water

= 0.11