Question

An ideal gas at 27°c is heated at constant pressure till its volume becomes three times. Then, what would be the temperature of gas?

Answer 1

hope it helps you...

Answer 2

Final temperature of gas is $627^0C$

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=v\\T_1=27^oC=(27+273)K=300K\\V_2=3v\\T_2=?$

Putting values in above equation, we get:

$\frac{v}{300}=\frac{3v}{T_2}\\\\T_2=900K=(900-273)^0C=627^0C$

Thus the temperature of gas is $627^0C$

Learn more about Charle's law

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