Question

an ideal gas exerts a pressure of 60 pa when its temperature is 400k and the number of molecules present in unit volume is n. Another sample of the same gas exerts a pressure of 30 pa when jts temperature is 300k how many molecules are present in unit volume of this second sample​

Answer 1

Answer:

30% temperature how many gas cylinder 4000 years number of the city and great places on the temperature percent of this

Answer 2

Answer:

The number of molecules present in a unit volume of the first and second samples​ is 0.017 mol/$m^{3}$ and 0.012 mol/$m^{3}$ respectively.

Explanation:

Given Data :
Pressure (P) = 60 Pa

Temperature (T) = 400 K

Volume (V) = 1 $m^{3}$

Number of molecules present = n

For Another Sample,

Pressure (P') = 30 Pa

Temperature (T') = 300 K

Volume (V') = 1 $m^{3}$

To Calculate :

The number of molecules present in a unit volume of this second sample​.

Calculations:

We can use the ideal gas law, which relates the pressure, volume, temperature, and number of particles of an ideal gas, we have

PV = nRT

$n = \frac{PV}{RT}$

Substituting the values, we get

$n = \frac{60 \times 1 }{8.31 \times 400 } = 0.017 mol/m^3$

Now, for the second sample, the number of moles (n') we have

$n' = \frac{30 \times 1}{8.31 \times 300}= 0.012 mol/m^{3}$

Therefore, The number of molecules present in a unit volume of the first and second samples​ is 0.017 mol/$m^{3}$ and 0.012 mol/$m^{3}$ respectively.

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