Question

An ideal gas expands in volume from 1×10⁻³ to 1 × 10⁻² m³ at 300 K against a constant pressure of 1×10⁵ Nm⁻². The work done is
(a) 270 kJ
(b) – 900 kJ
(c) – 900 J
(d) 900 kJ

Answer 1

w=-p×∆v

=10^5×(10×10^-3-1×10^-3)

=10^5×9×10^-3

=900j

Answer 2

Explanation: as it was an isobaric

we get this answer

Hope this will HELP you

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