An ideal gas expands isothermally from
10^3 m3 to 10^2 m3 at 300 K against a constant
pressure of 10^5 Nm-2. The work done on the gas is
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Answered by
6
Answer:
Work done due to change in volume against constant pressure is
W = - p(V2-V1)
= - 1 x 105 Nm-2 (1 x 10-2- 1 x 10-3)m3
Work done due to change in volume against constant pressure is
W = - p(V2-V1)
= - 1 x 105 Nm-2 (1 x 10-2- 1 x 10-3)m3
Answered by
3
Answer:
-900J
Explanation:
It is an easy question we just have to examine the situation and apply the formulae accordingly you can take a look at my solution and one thing very important is the Unit always take care about the units given in the answer. Hope it Help
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