An ideal gas heat engine operates in a carnot cycle between 227°C and 127°C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal)converted into work is equal to
Answers
Answered by
25
=> W = 1.2 kcal !
Explanation:
The efficiency of heat engine is n = 1 - T2/T1
or, W / Q1 = 1 - T2/T1
T2 = Temperature of sink
T1 = Temperature of source
W = Work done
Given, Q1 = heat absorbed from the source = 6kcal
T1 = 227 + 273 = 500 K
T2 = 127 + 273 = 400 K
W/6 = 100 / 500 or W = 1.2 kcal
Thus the amount of heat converted into work is 1.2 kcal !
Answered by
1
Answer:
♣️Amount of Heat converted into work is 1.2 kcal...♣️
♥️ Hope it will be helpful ☺️ thank you!!♥️
Similar questions