Question

An ideal gas in an enclosed space 27 ° C and has a particle kinetic energy of 150 J, if the gas temperature is now 327 ° C what is the kinetic energy?

Answer 1

T1 = 300 K, KE1=150 J
T2 = 600 K, KE2 = __?

KE = f • ½ k T
KE is proportional to absolute temperature

If the absolute temperature be 600/300 = 2 times back, the kinetic energy will be 2 times the original or 2 × (150 J) = 300 J

Answer 2

Translation kinetic energy of ideal gases are depends upon temperature ( in Kelvin) .

e.g K.E 1/K.E2 = T1/T2

here ,
K.E1 = 150 joule
T1 = 27°C = 273 + 27 = 300K
T2 = 327° C = 273 + 327 = 600K

now ,

150 Joule/K.E2 = 300/600

K.E2 = 150 × 2 = 300 K