Question

an ideal gas is compressed at constant pressure of 10 raise to power 5 Pascal until its volume is Hafte if the initial volume of the gas at 3 into 10 raise to power minus 2 m cube find the work done on the gas​

Answer 1

Given:

initial pressure on gas P1=0.72m of Hg

Initial volume of gas =V1=1L

final volume of gas=V2=0.9L

Let P2 be the final pressure on Gas 

From Boyle's law:P1V1=P2V2

P2=P1V1/V2

=0.72x1/0.9

=0.8m of Hg

So change in pressure is ΔP=P2-P1

=0.8-0.72

=0.08 m of Hg

Density of mercury=13600kg/m³

so ΔP=ρx gx0.08  N/m2

=13600x9.8x0.08

=10662.4 N/m2

As stress is defined as restoring force/area =pressure

Hence stress on gas is equal to change in  pressure 10662.4 N/m2