Question

An ideal gas undergoes a
cyclic process KLMNK as
shown in given P-V diagram.
The amount of work done by
the gas is:​

Answer 1

Answer:

option b is the correct answer.

Answer 2

Work done will be $-2P_oV_o.$

Given :

A P-V graph.

We have , to find the amount of work done by the gas.

In such questions the net work done by the gas is equal to the area under the curved form in the P-V graph.

In the given case amount of work done is equal to the area of triangle.

Therefore , Work Done , W = Area under the curve .

$W=Length \times Breadth$ ( of the rectangle )

$W=-(2P_o-P_o)(3V_o-V_o)\\\\W=-2P_oV_o$

Since , the direction is anti-clockwise .

It will be negative.

Hence, this is the required solution.

Learn More :

Heat and Thermodynamics

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