Physics, asked by keyurparmar, 11 months ago

An ideal monoatomic gas with pressure P, volume
Vand temperature T is expanded isothermally to
a volume 2V and a final pressure Pi. If the same
gas is expanded adiabatically to a volume 2V, the
final pressure is Pa. The ratio Pa÷Ps
is :​

Answers

Answered by danijaimi
0

Answer:

Explanation:

so p is inversely proportional to v

therefore Ps/i is p/2 in isothermal condition

now in adiabatic condition p is inversely proportoinal to v^gamma

so Pa/Ps/i=(Vs/Va/i)^gamma

we will get Pa=Ps/i*2^-8/3

therefore Pa/Ps/i=1/2^8/3

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