an ideal solution was obtained by mixing methanol and ethanol. if the partial vapour pressure of methanol and ethanol are 2.619 kPa and 4.556 KPa respectively, the composition of vapour(in terms of mole fraction) will be
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Final Answer : 0.365Methanol
0.634Ethanol.
Steps:
1) Find Total vapour pressure of solution by adding partial vapour pressures.
P(T) = 2.619+4.556= 7.175
2)We know that,
X(Methanol) = Partial Pressure (Methanol) / P(T)
= 2.619/7.175 = 0.365
3) Similarly,
X(Ethanol) = 4.556/7.175 = 0.634
Therefore, composition of Methanol and Ethanol (Mole fraction) is 0.365 and 0.634 respectively.
0.634Ethanol.
Steps:
1) Find Total vapour pressure of solution by adding partial vapour pressures.
P(T) = 2.619+4.556= 7.175
2)We know that,
X(Methanol) = Partial Pressure (Methanol) / P(T)
= 2.619/7.175 = 0.365
3) Similarly,
X(Ethanol) = 4.556/7.175 = 0.634
Therefore, composition of Methanol and Ethanol (Mole fraction) is 0.365 and 0.634 respectively.
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