In a regular polygon of n sides, each corner is at distance r from the centre. identical charges are placed at (n-1) corners at the centre the intensity is E and potential is V the ratio VByE has magnitude
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Final Answer :V/B= (n-1)r
Assuming there are (n-1) +q charges in (n-1) corners of regular hexagon.
Steps:
1) Let make this rectangular charge distribution a symmetric collection of charges by introducing a new charge +q and -q at the corner which is not filled.
2)Now, Cause of symmetry
Electric field at centre will be zero due to all +q charges due to symmetry.
So, Net Electric field will be due to -q charge only.
|E| = Kq/r^2
3) Since, Electric Potential is a scalar quantity.
So, V = (n-1) Kq/r
Now,
V/ E = (n-1) r
Assuming there are (n-1) +q charges in (n-1) corners of regular hexagon.
Steps:
1) Let make this rectangular charge distribution a symmetric collection of charges by introducing a new charge +q and -q at the corner which is not filled.
2)Now, Cause of symmetry
Electric field at centre will be zero due to all +q charges due to symmetry.
So, Net Electric field will be due to -q charge only.
|E| = Kq/r^2
3) Since, Electric Potential is a scalar quantity.
So, V = (n-1) Kq/r
Now,
V/ E = (n-1) r
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