Question

An ideal transformer has 400 turns in the primary
coil and carries 8 A current. If input power is 1 kW
then the number of turns in secondary coil to have
500 V output will be....

(1) 800
1600
(3) 100
(4) 200​

Answer 1

Answer:

the answer will be: 1600

Explanation:

here,

I(p)=8

P=1000

so, V(p)=125

V(s)=500

N(p)=400

we know,

N(s)=(Vs×np)/Vp=(500×400)/125=1600

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Answer 2

Answer:

for this question

the right answer is (B) 1600.