an illuminated object lies at a distance of 1.0 m from a screen a convex lens is used to form the image of object on a screen placed at a distance of 75 cm from the lens find the focal length of the lens and the magnification
Answers
Answered by
145
hey there
I am meritkshitij here
kindly refer to given attachment please
I am meritkshitij here
kindly refer to given attachment please
Attachments:
Akshat2002:
answer is in correct
v=75(+ve)
v=75cm(+ve)
u=100-75
=25cm(-ve)
By lens formula
1/f=1/v-1/u
=1/75-1/(-25)
=(1+3)/75
=4/75
So, f=75/4
=18.75
(b) m=v/u
=75/(-25)
=-3
Hope you got the right answer
u=100-75
=25cm(-ve)
By lens formula
1/f=1/v-1/u
=1/75-1/(-25)
=(1+3)/75
=4/75
So, f=75/4
=18.75
(b) m=v/u
=75/(-25)
=-3
Hope you got the right answer
distance of lens from screen is image distance
Answered by
29
Answer:
The focal length of the lens is 3m and the magnification of the lens is 0.75cm
Explanation:
Let the focal length of the convex lens is F
The distance between the object and the lens is U=1m=100cm
And the distance between screen is V=75cm
So the focal length can be derived for the convex lens is
1/F=1/V + 1/U
=>1/F=1/75 + 1/(-100)
=>1/F=1/300
=>F=300cm
So, F=3m
Focal length is 3m
Magnification of convex lens can be derived as M
We know magnification M= -(V/(-U))
=>M= 75/100
=>M= 0.75cm
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