Physics, asked by devnanda064, 1 year ago

An image 2/3rd the size the object is formed by a convex lens at a distance of 12cm from it. Find the focal length of the lens.
anyone help me?

Answers

Answered by AJAYMAHICH
16
In this case of convex lens, the size of the object is bigger than the size of the

image .Thus we can conclude that the image formed is real and inverted and also the

image formed is on the other side.According to the sign convention for lenses the

image distance on the other side will be positive .

Therefore v=12cm

For real and inverted image the magnification will be negative.therefore m= - 2/3



m = v/u

-2/3 = 12/u

u = -18 cm

1/v - 1/u = 1/f

f = 36/5 cm

f = 7.2 cm

Therefore the focal length is 7.2 cm

AJAYMAHICH: to iske sare cases yad krjo
AJAYMAHICH: rkho
devnanda064: except one case
AJAYMAHICH: haa sure
devnanda064: so hw do u knw it is not dat
devnanda064: i got it dude....it is bc m=v/u...so here 2/3...thats the thing!
AJAYMAHICH: hmm good
AJAYMAHICH: tysm dear
devnanda064: thx to u
AJAYMAHICH: welcome yr
Answered by Swayze
9

hy                              

friend                                    


here is your answer

i hope its helps you

                                                             

→ the size of the object  is bigger then .

→ the size of the image we can conclude that .

→ the image formed is real and inverted and the image formed is on .

→ the other side according to the sign convention for lenses the image distance on the other side will be positive .

                                                                                                                                           

  v = 12

 m = v/u

=   -2 /3 = 12 / u

= u = 12 x 3  / -2

= 1 / v or  - 1 / u  

= 1 / f

= 1 / 12   -   1  / 18

= 1 / f

= 2 + 3 / 36

= 1 / f

f = 36 / 5

= 7.2 cm

                                                                                                                     

thankyou

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devnanda064: but f=7.2 cm
Swayze: now its correct
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