An immersion heater rated 1000 W, 220 V is used to heat 0.01 m3 of water. Assuming that the power is supplied at 220 V and 60% of the power supplied is used to heat the water, how long will it take to increase the temperature of the water from 15°C to 40°C?
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Answer:
the answer will be 40% =780 v
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It will take 29.17 minutes for increasing the water temperature to 40 degree Celsius from 15 degree Celsius.
Explanation:
Given:
Power = P;
operating voltage = V
The immersion heater’s resistance is R = V2P = 48.4Ω.
Water mass can be shown as m = 1100× 1000 = 10 Kg
To raise the temperature of the given water mass, which is 10
Q = msθ = 1050000 J
To increase the water temperature, the time taken is t. The liberated heat is 60%. So, V2R × t × 60% = 1050000 J
⇒ t = 29.17 minutes
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