An impure sample of calcium carbonate contains 80% pure calcium carbonate 25 gram of impure sample reacted with excess of hydrochloric acid .Calculate the volume of carbon dioxide at STP obtained from this sample
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100g of impure calcium carbonate contain :
=80g pure calcium carbonate
25g of impure calcium carbonate sample contain =80100×25
=20g pure calcium carbonate
The desired equation is:
CaCO31mol100g+2HCl→CaCl2+CO222.4litreatNTP+H2O
100gpure CaCO3 liberate = 22.4 litre CO2
20g pure CaCO3 liberate =22.4100×20
=4.48 litre CO2 .
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
100g of impure calcium carbonate contain :
=80g pure calcium carbonate
25g of impure calcium carbonate sample contain =80100×25
=20g pure calcium carbonate
The desired equation is:
CaCO31mol100g+2HCl→CaCl2+CO222.4litreatNTP+H2O
100gpure CaCO3 liberate = 22.4 litre CO2
20g pure CaCO3 liberate =22.4100×20
=4.48 litre CO2 .
I HOPE IT HELPS U.
0BRAINLY01:
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