Physics, asked by nishitanagi1402, 1 year ago

An inductance of negligible resistance whose reactance is 22 W at 200 Hz is connected to 200 volts, 50 Hz power line. The value of inductance is(a) 0.0175 henry(b) 0.175 henry(c) 1.75 henry(d) 17.5 henry

Answers

Answered by Fatimakincsem
1

The value of inductance is   L = 0.0175 Henry

Explanation:

We are given:

  • Reactance  "R" = 22 W
  • Frequency "f" = 200 Hz
  • Voltage "v" = 200 volts
  • Power of the inductance "P" = 50 Hz

Solution:

X  L  = ωL = 2πnL

L=  2π / n X  L

L =  2 × 7 / 22×2 x  200   H

L = 0.0175 H

Thus the value of inductance is   L = 0.0175 Henry

Also learn more

A coil of resistance 10 ohm and an inductance of 5 henry is connected to a 100 volt battery. The energy stored in it is ?

https://brainly.in/question/11900603

​  

Answered by AadhilAjas
0

Answer:

The value of inductance is 0.0715 H.

Explanation:

Here;

Reactance of the inductor, XL=22 ohm

Frequency of the inductor, f=200 Hz

volt of the power line= 220 v

Frequency of the power line= 50 ohm

We know that;

XL= wL

=2× pi× f× L

=》Inductance,

L= XL/2× pi× f

=22/2×3.14×200

=0.0175 H

Resistance,

XĹ= 2× pi× f× L

= 2×3.14.50×0.0175

=5.5 ohm

Similar questions