The primary winding of a transformer has 100 turns and its secondary winding has 200 turns. The primary is connected to an A.C. supply of 120 V and the current flowing in it is 10 A. The voltage and the current in the secondary are(a) 240 V, 5 A(b) 240 V, 10 A(c) 60 V, 20 A(d) 120 V, 20 A
Answers
Answer:
Explanation:
=> Given :
Number of turns for primary winding, Np = 100 turns
number of turns for secondary winding, Ns = 200 turns
Voltage in the primary, Vp = 120 V
Voltage in the secondary, Vs = ?
=> Thus, The voltage and the current in the secondary are:
transformer ratio, Ns/Np = Vs/Vp ...(1)
200/100 = Vs/120
Vs = 200 * 120 / 100
Vs = 2 * 120
Vs = 240 V
=> When efficiency is tend to 100%, Power:
P = i * V
Thus, from power of primary and secondary,
ip * Vp = is * Vs
∴ Vp / Vs = is / ip ...(2)
From eq (1) and (2), we get
Ns/Np = Vs/Vp = ip / is
Vs/Vp = ip/is
240 / 120 = 10 / i_s
i_s = 10 * 120 / 240
i_s = 1200/240
i_s = 5 A
Thus, The voltage and the current in the secondary are 240 V and 5 A.
Answer:Number of turns for primary winding, Np = 100 turns
number of turns for secondary winding, Ns = 200 turns
Voltage in the primary, Vp = 120 V
Voltage in the secondary, Vs = ?
=> Thus, The voltage and the current in the secondary are:
transformer ratio, Ns/Np = Vs/Vp ...(1)
200/100 = Vs/120
Vs = 200 × 120 / 100
Vs = 2 × 120
Vs = 240 V
=> When efficiency is tend to 100%, Power:
P = i × V
Thus, from power of primary and secondary,
ip × Vp = is × Vs
∴ Vp / Vs = is / ip ...(2)
From eq (1) and (2), we get
Ns/Np = Vs/Vp = ip / is
Vs/Vp = ip/is
240 / 120 = 10 / i_s
i_s = 10 × 120 / 240
i_s = 1200/240
i_s = 5 A
Thus, The voltage and the current in the secondary are 240 V and 5 A.
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Explanation: