Question

An inductor 20 mH, a capacitor 100 μF and aresistor 50 Ω are connected in series acrossa source of emf, V = 10 sin 314 t. The powerloss in the circuit is
(1) 2.74 W
(2) 0.43 W
(3) 0.79 W
(4) 1.13 W

Answer 1

The power loss in the circuit is 0.79W.

P_av = (V_RMS/Z)^2 × R

∴P_av = (10/(√2)56)^2×50=0.79W

$\green {\huge{\boxed {0.79W}}}$

Answer 2

Explanation:

answer is

(c) 0.79 w

hope it helps