An inductor 200 mH, capacitor 500mu F and resistor 10 Omega are connected in series with a 100 V variable frequency ac source. What is the frequency at which the power factor of the circuit is unity?
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Explanation:
Here L=200mH=200×10^−3H=0.2H
C=500μF=500×10^-6=5×10^−4F
R=10Ω and Vrms=100V
now please refer attachment 1
R^2+(XL−XC)^2=R^2⇒XL−XC=0
or XL=XC (This is resonance condition)
now please reply attachment 2
hope it helps you mark as brainliest please
Attachments:
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