Question

an infinite conducting sheet has surface charge density Sigma the distance between two equipotential surfaces is are the potential difference between these two surfaces is

Answer 1

The potential difference between the two surface is given by  σr/ε₀

Explanation:

The surface charge density = σ

distance between the plates = r

we know that the electric field due to infinite conducting sheet,

E = σ/ε₀

And the potential difference between the two surface is given by:

V = Er

=> V = σ/ε₀ x r

=> V = σr/ε₀

Hence the potential difference between the two surface is given by σr/ε₀

Answer 2

The electric field from an infinitely charged sheet = sigma/epsilon.

Therefore, the potential difference, V = Er = sigma *r /epsilon.

It is a question from Electrostatics and the basis of it is from the surface charge density on a solid.

It can be defined as the total amount of charge, 'q' on an unit area 'A'.

Therefore, the surface charge density, sigma, can be defined as sigma = q/A.