Question

an ink container of cylindrical shape is filled with ink upto 91℅ball pen refills of length 12cm and inner diameter 2mm are filled upto 84℅ .if height and radius of the ink container are14cm and6cm respectively, find the number of refills that can be filled

Answer 1

Volume of ink in the container= $\pi r^{2} h= \frac{22*6*6*14*91}{7*100} = \frac{144144}{100} = 1441.44$ $cm^{3}$

Volume of ink in one refill= [tex] \pi r^{2} h= \frac{22*2*2*12*84}{7*10*10*100} = \frac{12672}{10000} = 1.2672 cm^{3} [/tex]

No. of refills that can be filled are= $\frac{Volume of ink in the container}{Volume of ink in one refill} = \frac{1441.44}{1.2672}$
= 1137.5 refills

Answer 2

GIVEN :

A cylindrical ink container is filled with ink up to 91℅ball pen refills of length 12cm and inner diameter 2mm are filled up to 84℅ .

height and radius of the ink container are 14cm and 6cm.

TO FIND :

Number of refills that can be filled.

SOLUTION:

◆Volume of the ink cylinder = πr^2h

= 3.14 × .06 ×.06 ×.14

= 1.58 ×10^-3 m^3

◆Volume of refills = πr^2h

= 3.14 × .001×.001 ×.12

=3.76 ×10^-7 m^3

◆Percentage of volume filled in refill =84%

◆Volume of ink filled in refills =

=3.76 ×10^-7 m^3 × 84/100.

=3.15 ×10^-7 m^3

◆Number of refills = 1.58 ×10^-3/ (3.15 ×10^-7)

= 5015.8 .

◆Since 91% are filled ,

◆Total number of refills

= 5015.8 × 91/100

=4564.4

=4564 refills.

ANSWER :

Total number of refills that can be filled= 4564 refills.