an ink container of cylindrical shape is filled with ink upto 91% ball pen refills of length 12 cm and inner diameter 2 mm are filled up to 84% if the height and radius of the ink container are 14 cm and 6 CM respectively find the numbers of reference that can be filled with the ink
Answers
Answered by
60
Given:
Length of the refill = 12 cm
Inner diameter of the refill = 2 mm
∴ Inner radius of refill = 22 mm = 1 mm = 0.1 cm
Now,
Volume of one refill = πr2h
= 227×(0.1)2×12
= 0.377 cm3
Because the refills are filled up to 84%, the volume of the ink filled in each refill is:
84100×0.377 cm3
= 0.3166 cm3
Also,
Height of the container = 14 cm
Radius of the container = 6 cm
Now,
Volume of the container = πr2h
= 227×62×14
= 1584 cm3
Because the container is filled with ink up to 91%, the volume of the ink filled in the container is:
91100×1584 = 1441.44 cm3
Thus, we have:
Number of refills that can be filled = Volume of the ink filled in the containerVolume of the ink filled in each refill
= 1441.44.3166
= 4552.87
Hence, the number of refills that can be filled is 4552.
Hope this answer help you
Length of the refill = 12 cm
Inner diameter of the refill = 2 mm
∴ Inner radius of refill = 22 mm = 1 mm = 0.1 cm
Now,
Volume of one refill = πr2h
= 227×(0.1)2×12
= 0.377 cm3
Because the refills are filled up to 84%, the volume of the ink filled in each refill is:
84100×0.377 cm3
= 0.3166 cm3
Also,
Height of the container = 14 cm
Radius of the container = 6 cm
Now,
Volume of the container = πr2h
= 227×62×14
= 1584 cm3
Because the container is filled with ink up to 91%, the volume of the ink filled in the container is:
91100×1584 = 1441.44 cm3
Thus, we have:
Number of refills that can be filled = Volume of the ink filled in the containerVolume of the ink filled in each refill
= 1441.44.3166
= 4552.87
Hence, the number of refills that can be filled is 4552.
Hope this answer help you
Answered by
40
Volume of ink in container
=91100×πr2h
=91100×π×(16)2×(14)Volume of ink in refill
=84100×πr2h
=84100×π×(210)2×(12)
Let the number of refills that can be filled be xNumber of refiils that can be filled
=Ink in container ink required for one refill x=91100×π×(16)2×(14)84100×π×(210)2×(12)
=13×14×25612×4100×12
=13×14×64×100144
=4550 .
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