Question

an insect crawls up 5 cm every second on a 60 cm vertical rod and then falls down 2 cm over the next second . how many secondswill it take to climb the rod ?

Answer 1

answer is 40 seconds.

the insect goes up by 5 cms in one sec.

it comes down by 2 cms in next one sec.

therefore distance travelled in 2 sec =  5-2 = 3cms.

since it travels 3cms in two sec.

therefore to travel 60 cms it will take:

=(60/3)2 sec

=20*2

=40seconds

Answer 2

Answer:

Step-by-step explanation:

Speed exists as a measure of how quickly an object moves from one place to another. It is equivalent to the distance traveled divided by time. It is possible to discover any of these three values utilizing the other two.

$&\text { speed }=\frac{\text { distance }}{\text { time }} \text {, time }=\frac{\text { distance }}{\text { speed }}, \text { distance }=\text { speed } \times \text { time }$

$&s=\frac{d}{t}, t=\frac{d}{s}, d=s t$

$&\mathrm{~s}=\text { speed (meters/second) }$

$&\mathrm{d}=\text { distance traveled (meters) }$

$&\mathrm{t}=\text { time (seconds) }$

This indicates,

In two seconds of duration, the insect crawls up $(5-2) \mathrm{cm}=3 \mathrm{~cm}$

This implies,

The distance traveled by the insect in

$1 \mathrm{sec}=\frac{3}{2} \mathrm{~cm}$

The time is taken by the insect to crawl up $60 \mathrm{~cm}$the vertical rod

$=\frac{60}{\frac{3}{2}} \mathrm{sec}=60 \times \frac{2}{3} \mathrm{sec}=20 \times 2 \mathrm{sec}=40 \mathrm{sec}$

The time taken by the insect to crawl up a 60 cm vertical rod stands 40sec.

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