An insects travels from a point a on the rim of cylindrical glass of radius 7cm and height 8cm. It has a constant speed and travels in a spiral on the outer surface of the cylinder. By the time the insect complete one full spiral and reaches the bottom of the cylinder at a point directly below the starting point. The total distance travelled by the insect is?
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Answer:
20√5 cm = 44.72 cm
Step-by-step explanation:
cylindrical glass of radius 7cm
=> circumference of Cylindrical Glass = 2 π R
π = 22/7 , R = 7 cm
=> circumference of Cylindrical Glass = 2 * (22/7) * 7
= 44 cm
Height = 8 cm
Distance travelled by insect = √( (circumference)² + ( Height)²)4
= √( ( 44)² + 8²)
= √ 1936 + 64
= √2000
= 20√5 cm
= 44.72 cm
The total distance travelled by the insect is 20√5 cm = 44.72 cm
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