an integer is choosen at random between 1and100 .find the probability that is : 1 )divisible by 8 2) not divisible by 8
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P(E) of getting no. divisible by 8=12÷100
=3 ÷25
P(E) of getting integers not divieible by 8=100-12÷100
=88÷100
=22÷25
=3 ÷25
P(E) of getting integers not divieible by 8=100-12÷100
=88÷100
=22÷25
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p(E) divisible by 8 =12/98
bcz it is given that the integer is between 1 and 100 so firstly we eliminate 1&100
p(E) not divisible by 8= 86/98
# hope it will help you#
thanks
bcz it is given that the integer is between 1 and 100 so firstly we eliminate 1&100
p(E) not divisible by 8= 86/98
# hope it will help you#
thanks
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