Question

An integer is choosen between 0 and 100 find the probability that the number is divisible by 3 and 5 both
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Answer 1

Answer:

An integer is chosen between 1 and 100 what is the probability that it is divisible by 8 and not divisible by 8.

SOLUTION:

In the question it is Given that the numbers are "between 1 and 100", we should exclude both 1 and 100.So we are left with 98 numbers.

i) Total numbers BETWEEN 1 and 100 are 98

Total Number of Outcomes= 98

Number divisible by 8 are : 8,16,24,32,49,48,56,64,72,80,88,96

Number of favourable outcomes = 12

Probability = Number of favourable outcomes / Total number of outcomes

Probability (divisible by 8) = 12/98 = 6/49

P((divisible by 8) = 6/49

ii) Number not divisible by 8 are : 98 -12 = 86

Number of favourable outcomes = 86

Probability = Number of favourable outcomes / Total number of outcomes

Probability (not divisible by 8) = 86/98 = 43/49

P((not divisible by 8) = 43/49

HOPE THIS WILL HELP YOU….

Step-by-step explanation: