an integer is chosen at random between 1 and 100 find probability of divisible by 8 and not divisible by 8?
Answers
Answered by
888
total number is 98
divisible by 8 are 8,16,24,32,40,48,56,64,72,80,88,96
so 12 numbers are divisible
so probability of divisible numbers=12/98=6/49
and probability of not divisible
98-12/98=86/98=43/49
divisible by 8 are 8,16,24,32,40,48,56,64,72,80,88,96
so 12 numbers are divisible
so probability of divisible numbers=12/98=6/49
and probability of not divisible
98-12/98=86/98=43/49
Anonymous:
why
so total will be 100 numbers na
out of Whixh 12 r divisible
I think I am Correct
yes you are correct
Ty @arjit
welxx
Answer is wrong how can you include 1 and 100 . It is between 1 and 100 i.e 2 to 99 .
Arjit it is in correct just apply your logic
oh common you say that it is not 100 its 98
Answered by
118
Answer:
Number of integers between 1 and 100: 2, 3 , 4, 5 , ..., 99
Total number of outcomes = 98
(i) Numbers which are divisible by 8 are: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96
Favourable Outcomes = 12
Probability that integer is divisible by 8, P(E) = 12/98 or 6/49
(ii) Probability that integer is not divisible by 8
P(E') = 1 - probability that it is divisible by 8
= 1 - 6/49
= 43/49
hope it helps.....
Similar questions