an integer is chosen at random between 1 and 100. find the probability that it is 1) divisble by 8. 2) not divisible by 8
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1. P=12/100
2. P=88/100
2. P=88/100
simran262:
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Answered by
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First number divisible by 8=8 (obviously)
Last number divisible by 8=96
Let no. of favourable outcomes = n
96=8+(n-1)8
n-1=11
n=12
1) P(E) = 12/100 = 0.12
2) P(not E) = 88/100 = 0.88
Last number divisible by 8=96
Let no. of favourable outcomes = n
96=8+(n-1)8
n-1=11
n=12
1) P(E) = 12/100 = 0.12
2) P(not E) = 88/100 = 0.88
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