Question

An integer is chosen at random between 1 and 100.Find the probability that it is :
(i) divisible by 8
(ii) not divisible by 8

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Step by Step Explanation...

Answer 1

Number of integers between 1 and 100:- 2, 3,4,5,...99

Total outcomes=98

so you can say total number of outcomes=98

Now , numbers which are divisible by 8 is 8,16,24,32,40,48,56,64,72,80,88,96

so total numbers which are divisible by 8 is 12.

so number of possible event is 12

Probability of number divisible by 8 is 12/98=6/49

probability of number not divisible by 8 is 1- probability number that is divisible by 8.

Probability not divisible by 8 is 1-6/49=(49-6)/49=43/49.

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Answer 2

1. when number is divisible by 8.... so see how many number is divisble by 8 , b/w 1 and 100? let me list all those numbers here...

.

8

16

24

32

40

48

56

64

72

80

88

96....  sototal nmber of event is 10+2= 12..... and total number of sample space is 100...

hence probability of choosing a random number b/w 1 and 100,which is divisible by 8 = (12/100) = 3/25  

2. in second part , not divisible by 8 = 1 - (divisible by 8) = 1 - (3/25) = 23/25

.

Hope you have understood ...