An integer is chosen between 0 and 100. What is the probability that it is ( i) divisible by 7 ( ii) not divisible by 9.
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1
100÷7 = 15.14....so p(e)=15/100= 3/20...
100÷9=11.11 so p(not e)=(100-9)/100=81/100
100÷9=11.11 so p(not e)=(100-9)/100=81/100
bkalpana0807198:
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Answered by
8
(i)No. of numbers divisible by 7=E=14
Total numbers=100
P(E)=14/100=0.14
(ii)No. of numbers not divisible by 9=E=89
Total numbers=100
P(E)=89/100=0.89
Hope dis worked for uu
plzz mrk as brainliest
Total numbers=100
P(E)=14/100=0.14
(ii)No. of numbers not divisible by 9=E=89
Total numbers=100
P(E)=89/100=0.89
Hope dis worked for uu
plzz mrk as brainliest
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