An interesting act performed at a variety show is to swing a bucket of water in a vertical circle such that water does not spill out while the bucket is inverted at the top of the circle. Derive the expression for minimum speed of the bucket at the top of the circle in terms of its radius R. Calculate the speed if the diameter of circle is 1.5 m.
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Answer:
Its because a centrifugal force
r
mv
2
acts on the water which is away from the center and opposite to force of gravity mg. If the mg is greater then
r
mv
2
water will spill out. but if
r
mv
2
is greater then mg water will not spill out of the bucket.
Note: for keeping the water in bucket while rotating it in a vertical circle you will have to keep the velocity above a certain value to make
r
mv
2
greater then mg.
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