An inverted cone of height 10 centimetre and base radius 6.4 centimetre contains water to a depth of 5,measured from the vertex.calculate the volume of water in the cone.
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volume = 1/3 pi r^2 h
where r is the radius of the base and h is the height.
Volume=1/3 x 3.14 x 4 x 15 =3.14 x 20 =62.8 cm^3
By similar triangle,
r / h = a / b , a=radius at the water level and b= height from the water level to bottom.
4 / 15 = a / 10
=> a = 10 x 4 / 15
=> a = 40 / 15 = 5 x 8 / 5 x 3 = 8/3 cm
Now, volume of the water
= 1/3 x pi x a^2 x b
=1/3 x 3.14 x (8/3)^2 x 10
=(31.4 / 3) x (8/3)^2
=74.4296 cm^3..........cm^3 means cubic cm.
where r is the radius of the base and h is the height.
Volume=1/3 x 3.14 x 4 x 15 =3.14 x 20 =62.8 cm^3
By similar triangle,
r / h = a / b , a=radius at the water level and b= height from the water level to bottom.
4 / 15 = a / 10
=> a = 10 x 4 / 15
=> a = 40 / 15 = 5 x 8 / 5 x 3 = 8/3 cm
Now, volume of the water
= 1/3 x pi x a^2 x b
=1/3 x 3.14 x (8/3)^2 x 10
=(31.4 / 3) x (8/3)^2
=74.4296 cm^3..........cm^3 means cubic cm.
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