An inverted cone of height 10 cm and Base radius 6.4 contains water to a depth of 5cm measured from the vertex . Calculate the volume of water in the cone.
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r of big cone=6.4 cm
H=10cm
Depth of the water in that cone=5 cm
Acc, to the statement they must be similar triangles.
Because { h of big cone}/depth of water = 2/1
So r/ R = 2/1
So, R of small cone = 3.2 cm
We have to find the volume of small cone
i.e
===1/3πr^2h
=1/3×22/7×3.2×3.2×5
=1/3×22/7×51.2
=1126.4/21
=53.683cm^3
so , volume of water in the cone = 53.683cm^3
Step-by-step explanation:
Hope this helps Thank you.............
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