Question

an inverted cone of height 15 cm and base radius 4 cm contains water to a depth of 10 cm. calculate the volume of water in the cone

Answer 1

Answer:

167.33

Step-by-step explanation:

πr^2h/3= 167.33

Answer 2

Volume of water in the cone is $357.13 cm^3$

Step-by-step explanation:

Height of cone = 15 cm

Radius of cone = 4 cm

This cone contains  water to a depth of 10 cm.

So, The shape formed till the depth of water is frustum

So, It forms similar triangles .

ratio of height to depth = 15:10

Let the smaller radius be r

So, Ratio of radii = 4:r

By property of similar triangles : Similar triangles are in the same ratio as the ratio of the length of their sides

So,. 15:10=4:r

So, r = 2.7

So, Smaller radius = 2.7 cm

Volume of frustum = $\frac{\pi}{3}h(R^2+r^2+Rr)$

h = 10 cm

R = 4 cm

r = 2.7 cm

So, volume of water in the cone = $\frac{\frac{22}{7}}{3}(10)(4^2+2.7^2+(4)(2.7))$

Volume of water in the cone=$357.13 cm^3$

#Learn more :

An inverted cone of vertical height 12cm and Base radius 9cm contains water to a depth of 4 cm. Find the area of the interior surface of the cone not in contact with the water.​

https://brainly.in/question/13779514