Question

An inverted differential manometer containing an oil of specific gravity 0.9 is connected to find the difference of pressures at two points of a pipe containing water.If the manometer reading is 40cm find the difference of pressures?​

Answer 1

Answer:

the difference of pressures is 3531.6 pa at two points of a pipe containing water

Explanation:

As we know that pressure is measured with the help of height difference in manometer

So the pressure is given as

$P = \rho g h$

here we know

$\rho = 0.9 \times 10^3$

$\rho = 900 kg/m^3$

$g = 9.81 m/s^2$

$h = 40 cm$

now by above formula

$P = 900(9.81)(0.40)$

$P = 3531.6 pa$

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Topic : Fluids Pressure

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Answer 2

Answer:

392.4

Explanation:

The equation for finding the pressure difference in a inverted differential manometer is

Pa - Pb = (density of liquid at first tube * g * h1 ) - ( " at second tube * g * h2 ) - ( " density of light liquid * g * h )

where g is gravitational constant and the loght liquid in this question is oil

the liquid at left and right limb are same in this question which is water

h1 - height difference liquid in left limb below the datum line

h2 - height of the liquid at right limb below the datum line

h - difference in height of light liquid

Here h1 is 40 cm which is 0.4 m

take h2 as x

so h is 0.4 + x

density of water - 1000

density of light liquid ( here oil) is 0.9 * 1000

By applying the values in the above equation we get the pressure difference ,

Pa - Pb = 392.4 N/m^2