Question

the area of two similar triangles are 169cm2 and 121cm2 if larger side is 26 CM of larger triangle Find the length of longest triangle

Answer 1

let the two triangles be abc and def
ab is the larger of abc and de is larger of def
ar abc/ar def=ab2/de2
169/121=26^2/de^2
de^2=676×121/169
=4×121
=484
de=√484
=22cm

Answer 2

Hiii. ...friends,

Here is ur answer,

If two triangles are similar.

A1/A2 = (Side1/side2) ^2

Here A1 =Area if first triangle,

A2=Area of second triangle,

Side1 = Length of one side of first triangle.

Side2 = Length of corresponding side of second triangle.

So, Given that.

A1=169 square.cm

A2=121sq.cm

Side1= 26cm

Let the side of the second triangle be x.

So,

=> 169/121 = (26/x)^2

=> 13/11= 26/x

=> x=11×2 =22cm.

:-)Hope it helps u.