Question

an inverted image three times the size of the object is obtained with an concave mirror of R is equal to 36 in the position of the images​

Answer 1

Answer:

Explanation:

It is given that,

Magnification

m=3

m=  

$\frac{-v}{u\\} \\f=\frac{R}{2} = -18$

t is given that a virtual image three times the size of the object is obtained with a concave mirror. So, v=−3u

From mirror’s formula

$\frac{1}{v} +\frac{1}{u} =\frac{1}{f} \\\frac{-1}{3u}+ \frac{1}{u}= \frac{1}{-18}$

u=−12cm

The distance of the object from the mirror u=12cm in front of concave mirror.

​