Question

an investment of 5000 incurred a loss by a certain percentage in the first year and showed a profit by the same percentage the next year.if at the end of two years the initial investment reduced to 4968.find the rate at which the investment first decresed and then increased.​

Answer 1

Answer:

8%

Step-by-step explanation:

let the rate at which the investment first decresed and then increased be X%

initially the investment is of 5000

then after loss (of X%) investment remain = 5000-(5000×X%)

now after profit (of X%) investment become

= [5000-(5000×X%)]+[{5000-(5000×X%)}×X%]

So, as per question;

[5000-(5000×X%)]+[{5000-(5000×X%)}×X%] = 4968

= [5000-(5000×X/100)] + [{5000-(5000×X/100)}×X/100] = 4968

= [5000- 50X] + [{5000-50X}×X/100] = 4968

= 5000- 50X + (5000X-50X^2)/100= 4968

=(500000- 5000X + 5000X-50X^2)/100= 4968

=(500000- 5000X + 5000X-50X^2)= 496800

=500000-50X^2= 496800

=50X^2= 500000-496800

=50X^2= 3200

=X^2= 3200/50=64

=X^2=64

=X=8

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Answer 2

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