Question

An ion with mass number 37 posses one unit of negative charge if the ion contains 11.1% more neutrons than electrons what is symol of ion?

Answer 1

let the number of electrons in the ion be x

then the number of neutrons ( 11.1% than electrons )= x+ 11.1/100 *x
                                                                                    = x+ 0.111x
                                                                                     = 1.111x
 number of electrons in the neutral atom ( one unit of negative charge less)                                                                            = x-1 
         

number of protons                                                    = x-1 

mass number = number of protons + number of neutrons 
                     37  = x-1 + 1.111x 
                2.111 x -1 = 37
             2.111x         = 38
           x                      = 38/ 2.111 
                                = 18 

number of protons  ( atomic number ) = x-1
                                                           = 18-1 
                                                          = 17
 the symbol of the ion is  cl whose atomic number is 17 and mass number is 37 

Answer 2

$\fbox\textcolor{orange}{\texttt{Answer = Cl(37,17)}}$

$\textcolor{indigo}{\texttt{Explanation :-}}$

Suppose no. of electrons = x

no. of neutrons = $x + \frac{11.1}{100}\times{x}\: = \:1.111x$

No. of electrons in the neutral atom = $x - 1$

No. of protons in the neutral atom =$x - 1$

Mass no. = no. of neutrons + no. of protons

ie, $37\:=\:1.111x+x-1$

$2.111x\:=\:37+1\:=\:38$

$x = \frac{38}{2.111}\:=\texttt{18}$

No. of protons = Atomic no. =

$x-1\:=\:18-1\:=\texttt{17}$

Hence the symbol of the ion is: $</h3><h3>\fbox{^{37}_{17}Cl}$