Question

An Iron ball and feather are both falling from a height of 10m. The time taken by the iron ball and feather to reach the ground is​

Answer 1

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Answer 2

Given:

• Height = 10m

To Find:

• The time taken by the iron ball and feather to reach the ground.

Solution:

In kinematics, the object is independent of mass.

∴ The iron ball and the feather would take the same time to reach the ground.

The formula to find the same is given by,

T = √(2h/g) → {equation 1}

Where "T" is the time taken, "g" is the acceleration due to gravity(g = 9.8m/$s^2$), and "h" is the height.

On substituting the values in equation1 we get,

⇒ T = √[(2×10)/9.8] {multiplying the etrms in bracket}

⇒ T = √ (20/9.8) {dividing the terms}

⇒ T = √2.040 [square root of the term}

⇒ T = 1.428s

∴ The time taken by the iron ball and feather to reach the ground = 1.428s.