An iron ball of mass 3 kg is released from height of 125m and falls freely to the ground . assuming that the value of (g) is 10m/s^2
,calculate the time taken by the ball to reach the ground? (please solve )
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Explanation:
NEGLECTING AIR RESISTANCE,
s = 125m
a (g) = 10 m/s^2
u = 0 m/s
By the 3rd equation of motion,
v^2 - u^2 = 2as
=> v^2 = 2 x 10 x 125
=> v^2 = 2500
=> v = 50 m/s
By the first equation of motion,
t = (v - u) /a
=> t = 50/10
=> t = 5s
If we neglect air resistance (i.e. in a vacuum), every body when falling freely from the same height, reaches the surface at the same time irrespective of its mass.
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