Question

An iron ball of mass 3 kg is released from height of 125m and falls freely to the ground . assuming that the value of (g) is 10m/s^2
,calculate the time taken by the ball to reach the ground? (please solve )
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Answer 1

Explanation:

S=125m

g=10m/s²

u=0m/s

v²=u²+2gS

v²=0²+2×10×125

v²=20×125

v=50m/s

t=(v-u)/g

t=(50-0)/10

t=50/10

t=5seconds

Answer 2

Answer:

5 sec

Explanation:

Let the initial velocity be 'u'.

u=0

S=h=125 m(distance)

g=10 m/s²

t=?

S=ut+1/2gt²

125=0×t+1/2×10×t²

125=5t²

125/5=t²

t=√125/5

t=5

Therefore , the time taken by iron ball to reach the ground is 5 sec.